ajax新手筆記

使用PHP、MySQL、ajax做連動下拉選單

【list.php】

--------------------------------------------------

<form name="form1" method="post" action="./mgr_main.php" target="topFrame">

<select name=dataClass id=dataClass size=1>

<option>選擇分類</option>

<?php

$i = 0;

$sqlResult = mysqli_query($link, "select className from class_table");

while($classResult = mysqli_fetch_array($sqlResult))

{

$className_var[$i] = $classResult['className'];

echo "<option value=".$className_var[$i].">".$className_var[$i]."</option>";

$i++;

}

$listNumber = $i;

?>